What is the y-coordinate of the point that divides the
directed line segment from J to k into a ratio of 5:1?

O -8
O -5
O 0
O 6

What is the y-coordinate of the point that divides the directed line segment from J to k into a ratio of 5:1? O -8 O -5 O 0 O 6 class=

Answer :

MrRoyal

Answer:

[tex]y = 0[/tex]

Step-by-step explanation:

Given

Line segment JK

[tex]J = (1,-10)[/tex]

[tex]K = (7,2)[/tex]

Ratio; [tex]m:n= 5:1[/tex]

Required

Find the coordinates of y

From the question; the formula to use is

[tex]y = (\frac{m}{m+n})(y_2 - y_1) + y_1[/tex]

We have that; m = 5; n = 1

[tex]J =(x_1, y_1) = (1,-10)[/tex]

Hence, [tex]y_1 = -10[/tex]

[tex]K = (x_2,y_2)= (7,2)[/tex]

Hence, [tex]y_2 =2[/tex]

Substitute the above values in the given formula;

[tex]y = (\frac{m}{m+n})(y_2 - y_1) + y_1[/tex] becomes

[tex]y = (\frac{5}{5+1})(2 - (-10)) + (-10)[/tex]

Solve brackets

[tex]y = (\frac{5}{6})(2 +10)) - 10[/tex]

[tex]y = (\frac{5}{6})(12)) - 10[/tex]

Open bracket

[tex]y = \frac{5}{6} * 12 - 10[/tex]

[tex]y = \frac{5*12}{6}- 10[/tex]

[tex]y = \frac{60}{6}- 10[/tex]

[tex]y = 10 - 10[/tex]

[tex]y = 0[/tex]

Answer: 0

Step-by-step explanation:

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