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On a coordinate plane, a parabola opens up in quadrant 1. It goes through (2, 12), has a vertex at (5, 3), and goes through (8, 12). Write the equation of the function whose graph is shown. y = (x + )2 +.

On a coordinate plane, a parabola opens up in quadrant 1. It goes through (2, 12), has a vertex at (5, 3), and goes through (8, 12). Write the equation of the f class=

Answer :

Luv2Teach

Answer:

Step-by-step explanation:

You have a vertex coordinate and 2 points. In order to write the equation for that parabola, you only need the vertex and one point. We will fill in the following work form of the parabola:

[tex]y=a(x-h)^2+k[/tex] , where h and k are from the vertex and x and y are from the point. Filling in:

[tex]12=a(8-5)^2+3[/tex] and

[tex]12=a(3)^2+3[/tex] and

[tex]12=9a+3[/tex] and

9 = 9a s0

a = 1.

Now we can write the equation, filling in a, the only unknown we had, which we now know is 1:

[tex]y=1(x-5)^2+3[/tex]

Answer:

y =  1 (x +  -5 )2 + 3

Step-by-step explanation:

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