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If you were constructing a 99% confidence interval of the population mean based on a sample of n 1) = 25 where the standard deviation of the sample S = 0.05, the critical value of t will be

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Answer:

We want a confidence of 99% so then the significance level would be 1%

The degrees of freedom are given by:

[tex] df = n-1= 25-1=24[/tex]

And the critical value using the significance level [tex]\alpha=0.01[/tex] and [tex]\alpha/2 =0.005[/tex] and the critical value would be:

[tex] t_{\alpha/2}= \pm 2.797[/tex]

Step-by-step explanation:

We know the following info :

[tex] s= 0.05[/tex] represent the standard deviation from the sample

[tex] n = 25[/tex] represent the sample size selected

We want a confidence of 99% so then the significance level would be 1%

The degrees of freedom are given by:

[tex] df = n-1= 25-1=24[/tex]

And the critical value using the significance level [tex]\alpha=0.01[/tex] and [tex]\alpha/2 =0.005[/tex] and the critical value would be:

[tex] t_{\alpha/2}= \pm 2.797[/tex]

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