Answer :
Answer:
[tex] 4x^5\sqrt[3]{3x} [/tex]
Step-by-step explanation:
I'm not sure I understand the problem, but I think it's this:
[tex] \sqrt[3]{16x^7} \times \sqrt[3]{12x^9} = [/tex]
[tex]= \sqrt[3]{16 \times 12 \times x^{16}}[/tex]
[tex]= \sqrt[3]{192 \times x^{15} \times x}[/tex]
[tex] = \sqrt[3]{64 \times 3 \times (x^5)^3 \times x} [/tex]
[tex] = \sqrt[3]{4^3 \times 3 \times (x^5)^3 \times x} [/tex]
[tex] = 4x^5\sqrt[3]{3x} [/tex]
The product of the given expression [tex]\sqrt[3]{16x^7} \times \sqrt[3]{12x^9}[/tex] will be [tex]4x ^5\sqrt[3]{3x}[/tex].
[tex]4x ^5\sqrt[3]{3x}[/tex].
What are some basic properties of exponentiation?
If we have a^b then 'a' is called the base and 'b' is called power or exponent and we call it "a is raised to the power b" (this statement might change from text to text slightly).
Exponentiation(the process of raising some number to some power) have some basic rules as:
[tex]a^b \times a^c = a^{b+c} \\\\^n\sqrt{a} = a^{1/n} \\\\[/tex]
The given expression is follows as
[tex]\sqrt[3]{16x^7} \times \sqrt[3]{12x^9} \\\\\sqrt[3]{16\times 12 \times x^{16}} \\\\\sqrt[3]{192\times x \times x^{15}} \\\\\sqrt[3]{64\times 3\times x \times (x^{5})^3} \\\\\sqrt[3]{4^3 \times 3\times x \times (x^{5})^3}[/tex]
[tex]4x ^5\sqrt[3]{3x}[/tex]
Therefore, the product of the given expression [tex]\sqrt[3]{16x^7} \times \sqrt[3]{12x^9}[/tex] will be [tex]4x ^5\sqrt[3]{3x}[/tex].
Learn more about exponentiation here:
https://brainly.com/question/26938318
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