Answer :
Volume of Aluminium cylinder = mass ÷ density
= 13.1 g ÷ 2.70 g / cm³
= 4.85 cm³
If Volume of Cylinder = πr²l
then 4.85 cm³ = πr²(2.60cm)
thus r² = [tex]\frac{4.85 cm ^{3} }{ \pi * 2.6 cm}[/tex]
∴ r ≈ √(0.594 cm)
≈ 0.771 cm
= 13.1 g ÷ 2.70 g / cm³
= 4.85 cm³
If Volume of Cylinder = πr²l
then 4.85 cm³ = πr²(2.60cm)
thus r² = [tex]\frac{4.85 cm ^{3} }{ \pi * 2.6 cm}[/tex]
∴ r ≈ √(0.594 cm)
≈ 0.771 cm