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The maximum acceleration of a fist in a karate punch is 4200 m/s2. The mass of the
fist is 0.60 kg. If the fist hits a wooden block, what force does the wood place on the
fist?

Answer :

Answer:

F = 2520 N

Explanation:

We have,

The maximum acceleration of a fist in a karate punch is 4200 m/s². The mass of the fist is 0.6 kg.

It is required to find the force that the wood place on the fist. Force is given by the product of mass and its acceleration such that,

F = ma

[tex]F=0.6\times 4200\\\\F=2520\ N[/tex]

So, the force of 2520 N is acting on the wood.

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