Answer :

TheAnimeGirl

Answer:

[tex] \frac{1}{2} {r}^{2} ( \frac{1}{2}\pi - 1)[/tex]

option D is the right option.

solution,

Area of shaded region:

Area of sector-Area of ∆

[tex] = \frac{90}{360} \times \pi {r}^{2} - \frac{1}{2} \times r \times r \\ = \frac{1}{4} \pi {r}^{2} - \frac{1}{2} {r}^{2} \\ = \frac{1}{2} {r}^{2} ( \frac{1}{2} \pi - 1)[/tex]

Hope this helps...

Good luck on your assignment..

The  expression in square units that represents the area of the shaded segment of C. Geometry is [tex]\frac{1}{2}r^2(\frac{1}{2}\pi - 1)[/tex]

Calculation of the expression:

Since we know that

The area of the shaded region = Area of the sector - an area of a triangle

So,

[tex]= \frac{90}{360} \times \pi r^2 - \frac{1}{2} \times r\times r\\\\ = \frac{1}{4}\pi r^2 - \frac{1}{2}r^2 \\\\= \frac{1}{2}r^2(\frac{1}{2}\pi - 1)[/tex]

hence, The  expression in square units that represents the area of the shaded segment of C. Geometry is [tex]\frac{1}{2}r^2(\frac{1}{2}\pi - 1)[/tex]

Learn more about area here: https://brainly.com/question/2502351

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