Answer :
Answer:
18.9 J
Explanation:
The computation of the gravitational potential energy is shown below:
In this question, we use the law of conservation of energy
As we know that
[tex]E=U+K = mgh + \frac{1}{2}mv^2[/tex]
where
U = potential energy
And K = kinetic energy
h = 0
u = 0
Now placing given values to the above formula
[tex]E_i = K_i = \frac{1}{2}mv^2[/tex]
[tex]= \frac{1}{2}(0.25 kg)(12.3 m/s)^2[/tex]
[tex]=18.9 J[/tex]
As we know that
Total mechanical energy equivalent to potential energy
[tex]E_f = U_f[/tex]
However, the mechanical energy is conserved, Ef = Ei, so
[tex]U_f = K_i[/tex]
Therefore the potential energy at the top of the flight is
[tex]U_f = K_i = 18.9 J[/tex]