Answer :
Answer:
I guess that the equations are:
P*P = Q*6
and
Q - P = 3
now, in the second equation we have:
Q = 3 + P
we can replace it in the first equation:
P^2 = (3 + P)*6 = 6P + 18
then we have the quadratic equation:
P^2 -6P - 18 = 0
Now, we can find the solutions of these equations are:
[tex]P = \frac{+6 +-\sqrt{(-6)^2 - 4*1*(-18)} }{2} =\frac{6 +- 10.4}{2}[/tex]
then the solutions are:
P = (6 + 10.4)/2 = 8.2
and
P = (6 - |0.4)/2 = -2.2
Then, if P = 8.2, then we must have Q = 11.2
and if P = -2.2, then Q = 0.8