Answer :
Answer:
Step-by-step explanation:
find the slope
[tex]\frac{4-8}{-5-(-3)} =\frac{-4}{-2} \\\\slope=2\\y=mx+b\\y=2x+b\\[/tex]
take a coordinate to fill in
[tex](-5,4)\\y=-5\\x=4\\-5=2(4)+b\\-5=8+b-8 -8\\-13=b\\[/tex]
this means that the equation is y=2x-13
and if you add m and b
you get :-11
I HOPE THIS HELPS
Answer:
7/2
Step-by-step explanation:
Let $A = (-3,8)$ and $B = (-5,4)$. The midpoint of $\overline{AB}$ is $\left( \frac{(-3) + (-5)}{2}, \frac{8 + 4}{2} \right) = (-4,6)$.
The slope of $\overline{AB}$ is $\frac{8 - 4}{(-3) - (-5)} = 2$, so the slope of the perpendicular bisector of $\overline{AB}$ is $-\frac{1}{2}$. Therefore, the equation of the perpendicular bisector is given by
\[y - 6 = -\frac{1}{2} (x + 4).\]Isolating $y,$ we find
\[y = -\frac{1}{2} x + 4.\]