Answer:
[tex] \boxed{\huge{\sf f(x) = 1}} [/tex]
Given:
[tex] \sf f(x) = \frac{x}{2 + 8} [/tex]
To Find:
[tex] \sf f(x) \: when \: \bold{x} = 10[/tex]
Step-by-step explanation:
[tex] \sf Evaluate \: f(x) = \frac{x}{2 + 8} \: where \: \bold{x} = 10 : \\ \sf \implies f(x) = \frac{x}{2 + 8} = \frac{10}{2 + 8} \\ \\ \sf 2 + 8 = 10 : \\ \sf \implies f(x) = \frac{10}{ \boxed{\sf 10}} \\ \\ \sf \frac{ \cancel{\sf 10}}{ \cancel{\sf 10}} = 1 : \\ \sf \implies f(x) = 1[/tex]
