Need help finding the missing length to the attached triangle.

Answer:
65 units
Step-by-step explanation:
Let the length of the perpendicular dropped from the right angle to the hypotenuse be h units.
Now by geometric mean property:
[tex]h = \sqrt{144 \times 25} \\ h = 12 \times 5 \\ h = 60 \: units \\ Next \: by \: Pythagoras \: Theorem: \\ {x}^{2} = {h}^{2} + {25}^{2} \\ {x}^{2} = {60}^{2} + {25}^{2} \\ {x}^{2} = 3600 + 625 \\ {x}^{2} = 4225 \\ x = \sqrt{4225} \\ \huge \red{ \boxed{x = 65\: units }}[/tex]