Answer:
The right answer is the first option, [tex]tg= \frac{\sqrt{105}}{4}[/tex]
Step-by-step explanation:
The tg is the ratio of the opposite cathet to the adjacent cathet
.
Here b is the opposite cathet, с is the hypotenuse and b is an adjacent cathet.
[tex]tg = \frac{b}{a}[/tex]
Let's find b.
[tex]c^2=a^2+b^2\\ b^2=c^2-a^2\\ b^2=22^2-8^2\\ b^2=484-64\\ b^2=420\\ b=\sqrt{420} = \sqrt{2*21*2*5} = 2\sqrt{105}[/tex]
Now let's find tgθ.
[tex]tg = \frac{b}{a} \\ tg = \frac{2\sqrt{105}}{8} \\ tg=\frac{\sqrt{105}}{4}[/tex]
