Answer :
Answer:
375 and 450
Explanation:
The computation of the initial and the final temperature is shown below:
In condition 1:
The efficiency of a Carnot cycle is [tex]\frac{1}{6}[/tex]
So, the equation is
[tex]\frac{1}{6} = 1 - \frac{T_2}{T_1}[/tex]
For condition 2:
Now if the temperature is reduced by 75 degrees So, the efficiency is [tex]\frac{1}{3}[/tex]
Therefore the next equation is
[tex]\frac{1}{3} = 1 - \frac{T_2 - 75}{T_1}[/tex]
Now solve both the equations
solve equations (1) and (2)
[tex]2(1 - T_2/T_1) = 1 - (T_2 - 75)/T_1\\\\2 - 1 = 2T_2/T_1 - (T_2 - 75)/T_1\\\\ = (T_2 + 75)/T_1T_1 = T_2 + 75\\\Now\ we\ will\ Put\ the\ values\ into\ equation (1)\\\\1/6 = 1 - T_2/(T_2 + 75)\\\\1/6 = (75)/(T_2 + 75)[/tex]
T_2 + 450 = 75
T_2 = 375
Now put the T_2 value in any of the above equation
i.e
T_1 = T_2 + 75
T_1 = 375 + 75
= 450