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what is the coordinate of the vertex of the parabola y-2=1/12(x+10) a. ( 10,-2) b. (-10,2) c. (-2,10) d. (2.-10)

Answer :

Answer:

[tex] y-a= c(x-b)^2[/tex]

With the vertex [tex] V= (b,a)[/tex]

We see that b = -10 and a = 2 and then the vertes wuld be:

[tex] V= (-10,2)[/tex]

And the best option is:

b. (-10,2)

Step-by-step explanation:

For this problem we have the following function:

[tex] y-2 = \frac{1}{2} (x+10)[/tex]

And if we compare this expression with the general expression for a parabola given by:

[tex] y-a= c(x-b)^2[/tex]

With the vertex [tex] V= (b,a)[/tex]

We see that b = -10 and a = 2 and then the vertes wuld be:

[tex] V= (-10,2)[/tex]

And the best option is:

b. (-10,2)

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