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A population has a standard deviation of 50. A random sample of 100 items from this population is selected. The sample mean is determined to be 600. At 95% confidence, the margin of error is

Answer :

Answer:

Margin of error is 9.8

Step-by-step explanation:

Using the formular for the margin of error

The margin of error = z* (sd/√n)

Where z is the z score for the desired confidence level = 1.96, sd is the population standard deviation = 50 and n is the sample size = 100

Thus

Margin of error = 1.96 (50/√100)

= 1.96 (50/10)

= 1.96 (5)

= 9.8

Margin of error is 9.8

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