COF
A normal distribution curve, where x = 70 and o = 15,
was created by a teacher using her students' grades.
What information about their performances can be
obtained by analyzing the curve?

Answer :

Answer:

[tex] X \sim N(\mu= 70, \sigma=15)[/tex]

From this info and using the empirical rule we know that we will have about 68% of the scores between:

[tex] \mu -\sigma = 70-15=55[/tex]

[tex] \mu +\sigma = 70+15=85[/tex]

95 % of the scores between:

[tex] \mu -2\sigma = 70-2*15=40[/tex]

[tex] \mu +2\sigma = 70+2*15=100[/tex]

And 99.7% of the values between

[tex] \mu -3\sigma = 70-3*15=25[/tex]

[tex] \mu +3\sigma = 70+3*15=115[/tex]

Step-by-step explanation:

For this problem we can define the random variable of interest as "the student grades" and we know that the distribution for X is given by:

[tex] X \sim N(\mu= 70, \sigma=15)[/tex]

From this info and using the empirical rule we know that we will have about 68% of the scores between:

[tex] \mu -\sigma = 70-15=55[/tex]

[tex] \mu +\sigma = 70+15=85[/tex]

95 % of the scores between:

[tex] \mu -2\sigma = 70-2*15=40[/tex]

[tex] \mu +2\sigma = 70+2*15=100[/tex]

And 99.7% of the values between

[tex] \mu -3\sigma = 70-3*15=25[/tex]

[tex] \mu +3\sigma = 70+3*15=115[/tex]

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