Answer :
Answer:
Step-by-step explanation:
y=12x−2. parallel lines have the same slope 12
find b at point (3,-2)
y=12x+b
-2=12(3)+b
-2-36=b
b=-36
the equation has to be y=12x-38
when you input the point(3,-2)
-2=12(3)-38
-2=-2 correct
The equation of line is [tex]y=12x-38[/tex] which is parallel to given line [tex]y=12x-2[/tex]
Equation of parallel line given is, [tex]y=12x-2[/tex]
Compare above equation of line from [tex]y=mx+c[/tex]
Since, all parallel lines have same slope.
Equation of line become,
[tex]y=12x+c[/tex]
Since, line passing through point (3, -2).
[tex]-2=12(3)+c\\\\c=-2-36=-38[/tex]
Hence, equation of line is [tex]y=12x-38[/tex] which is parallel to line [tex]y=12x-2[/tex]
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