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A centrifuge's angular velocity is initially at 159.0 radians/second to test the stability
of a high speed drill component. It then increases its angular velocity to 999.0
radians/second. If this is achieved in 4,100.0 radians what is the angular acceleration
of the centrifuge?

Answer :

MathPhys

Answer:

118.6 rad/s²

Explanation:

Δθ = 4100.0 rad

ω₀ = 159.0 rad/s

ω = 999.0 rad/s

Find: α

ω² = ω₀² + 2αΔθ

(999.0 rad/s)² = (159.0 rad/s)² + 2α (4100.0 rad)

α = 118.6 rad/s²

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