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PLEASE HELP ASAP !! Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. QUESTION: Find the average rate of change of each function over the interval [0, 3]. Match each representation with its respective average rate of change 3, -3 ,-2,6,-1,5

PLEASE HELP ASAP !! Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. QUESTION: Find the average rate of change of each fun class=
PLEASE HELP ASAP !! Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. QUESTION: Find the average rate of change of each fun class=
PLEASE HELP ASAP !! Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. QUESTION: Find the average rate of change of each fun class=

Answer :

Answer:

Average rate of change of functions r, q, p, s are 5, 3, -2 and 6 respectively.

Step-by-step explanation:

The formula for average rate of change of f(x) over [a,b] is

[tex]m=\dfrac{f(b)-f(a)}{b-a}[/tex]

The given function is

[tex]r(x)=x^2+2x-5[/tex]

[tex]r(0)=(0)^2+2(0)-5=-5[/tex]

[tex]r(3)=(3)^2+2(3)-5=10[/tex]

Now,

[tex]m_1=\dfrac{r(3)-r(0)}{3-0}[/tex]

[tex]m_1=\dfrac{10-(-5)}{3}=5[/tex]

From the graph it is clear that q(0)=-4 and q(3)=5.

[tex]m_2=\dfrac{q(3)-q(0)}{3-0}[/tex]

[tex]m_2=\dfrac{5-(-4)}{3}=3[/tex]

It is given that  function p has as x-intercept at (3,0) and a y-intercept at (0,6). It menas p(0)=6 and p(3)=0.

[tex]m_3=\dfrac{p(3)-p(0)}{3-0}[/tex]

[tex]m_3=\dfrac{0-6}{3}=-2[/tex]

From the given table it is clear that s(0)=-13 and s(3)=5.

[tex]m_4=\dfrac{s(3)-s(0)}{3-0}[/tex]

[tex]m_4=\dfrac{5-(-13)}{3}=6[/tex]

Therefore, the average rate of change of functions r, q, p, s are 5, 3, -2 and 6 respectively.

Answer:

5, 3, -2 and 6

Step-by-step explanation:

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