When water freezes, it expands about nine percent. What would be the pressure increase inside your automobile engine block if the water in there froze? The bulk modulus of ice is 2.0 × 109 N/m2, and 1 ATM = 1.01 × 105 N/m2.

Answer :

Answer:

The pressure increase inside the automobile engine block is 1782.18 ATM

Explanation:

Given;

the change in volume of water, ΔV = 9%

the bulk modulus of ice, K = 2 x 10⁹ N/m²

Bulk modulus is given by;

[tex]K = -V\frac{dP}{dV}[/tex]

for pressure increase in the automobile engine block, when the water in there froze;

[tex]dP = K(\frac{dV}{V} )\\\\dP = K(\frac{0.09V}{V} )\\\\dP = 0.09K\\\\dP = 0.09 (2*10^9)\\\\dP = 1.8 *10^{8} \ N/m^2\\\\dP = 1782.18 \ ATM[/tex]

Therefore,  the pressure increase inside the automobile engine block is 1782.18 ATM

The pressure increase inside your automobile engine block will be 1782.18 atm. The force involved vertical to the surface of an object per unit area is pressure.

What is pressure?

The force applied perpendicular to the surface of an item per unit area across which that force is spread is known as pressure.

It is denoted by P. The pressure relative to the ambient pressure is known as gauge pressure.

The given data in the problem is;

ΔV is the  change in volume of water = 9%

K is the bulk modulus of ice = 2 x 10⁹ N/m²

dP is the change in the presure=?

The bulk modulus is found as;

[tex]\rm K=-V \frac{dp}{dv} \\\\[/tex]

The change in the presure is obtained as;

[tex]\rm dP = K\frac{dV}{V} \\\\ \rm dP = K\frac{0.09V}{V} \\\\ \rm dP = 0.09 K \\\\ \rm dP = 0.09 \times 2 \times 10^9 \\\\ \rm dP = 1.8 \times 10^8 \\\\ \rm dP =1782.18 \ atm[/tex]

Hence the pressure increase inside your automobile engine block will be 1782.18 atm.

To learn more about the pressure refer to the link;

https://brainly.com/question/356585

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