The graph below shows the survey results for a group of students who were asked how many honors classes they have taken and how many elective classes: How many elective classes would a student likely have taken if he or she has taken 12 honors classes? 15, because y = one halfx + 9 12, because y = y = negative one halfx + 9 6, because y = one halfx + 9 3, because y = negative one halfx + 9

The graph below shows the survey results for a group of students who were asked how many honors classes they have taken and how many elective classes: How many class=

Answer :

thepingu

Answer:

3, because [tex]y=-\frac{1}{2}x+9[/tex].

Step-by-step explanation:

Looking at this graph, we can start to determine the equation for it.

The y-intercept of this graph is 9, therefore there will be a constant of 9.

We can find the slope by looking at rise over run. It vertically travels -1 for every 2 horizontally. So the slope is [tex]-\frac{1}{2}[/tex].

Making this into an equation gets us  [tex]y=-\frac{1}{2}x+9[/tex].

Now we can substitute 12 into this equation as x.

[tex]y=-\frac{1}{2}(12)+9\\ y=-6+9\\y=3[/tex]

Hope this helped!

Answer:

the other person is correct! C:

Step-by-step explanation:

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