Answer:
Two solutions: -0.12 and 1.75.
Step-by-step explanation:
The quadratic formula is:
[tex]\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}[/tex]. Assuming that the x² term is a, the x term is b, and the constant is c, we can plug the values into the equation.
[tex]\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {8^2 - 4\cdot-4.9\cdot1} }}{{2\cdot-4.9}}} \end{array}[/tex]
[tex]\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {64 + 19.6} }}{{-9.8}}} \end{array}[/tex]
[tex]\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {83.6} }}{{-9.8}}} \end{array}[/tex]
[tex]\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {9.14} }}{{-9.8}}} \end{array}[/tex]
[tex]\frac{-8 + 9.14}{-9.8} = -0.12[/tex]
[tex]\frac{-8-9.14}{-9.8} =1.75[/tex]
Hope this helped!
