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Suppose that [tex]\alpha[/tex] is inversely proportional to [tex]\beta[/tex]. If [tex]\alpha=4[/tex] when [tex]\beta=9[/tex], find [tex]\alpha[/tex] when [tex]\beta=-72[/tex]

Answer :

Stephen46

Answer:

The answer is

[tex] \alpha = - \frac{1}{2} [/tex]

Step-by-step explanation:

From the question

[tex]\alpha[/tex] is inversely proportional to [tex]\beta[/tex] is written as

[tex] \alpha = \frac{k}{ \beta } [/tex]

where k is the constant of proportionality

When

[tex]\alpha[/tex] = 4

[tex]\beta[/tex] = 9

Substituting the values into the formula

we have

[tex]4 = \frac{k}{9} [/tex]

cross multiply

k = 4 × 9

k = 36

So the formula for the variation is

[tex] \alpha = \frac{36}{ \beta } [/tex]

when

[tex]\beta[/tex] = - 72

That's

[tex] \alpha = \frac{36}{ - 72} [/tex]

Simplify

We have the final answer as

[tex] \alpha = - \frac{ 1}{2} [/tex]

Hope this helps you

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