Answered

Solve for xxx. 12x+7 4012x+7 4012, x, plus, 7, is less than, minus, 11, start color #ed5fa6, start text, space, O, R, space, end text, end color #ed5fa6, 5, x, minus, 8, is greater than, 40 Choose 1 answer: Choose 1 answer: (Choice A) A x \dfrac{48}{5}x> 5 48 ​ x, is greater than, start fraction, 48, divided by, 5, end fraction (Choice B) B -\dfrac32 \dfrac32x> 2 3 ​ x, is greater than, start fraction, 3, divided by, 2, end fraction or x<\dfrac{48}{5}x< 5 48 ​ x, is less than, start fraction, 48, divided by, 5, end fraction (Choice D) D There are no solutions

Answer :

abidemiokin

Answer:

x < -3/2 and x>48/5

Step-by-step explanation:

Given  the inequality function 12x+7< -11 and 5x-8>40, we are to solve for the value of x. To solve for x, the following steps must be followed.

For the inequality 12x+7< -11

Step 1: Subtract 7 from both sides of the inequality

12x+7-7< -11-7

12x < -18

Step 2: Divide both sides of the inequality by 12

12x/12 < -18/12

x < -3/2 .............. 1

For the inequality 5x-8> 40;

Step 1: Add 8 to both sides of the inequality

5x-8+8 > 40+8

5x > 48

Step 2: Divide both sides of the inequality by 5

5x/5 > 48/5

x>48/5....... 2

Combining equation 1 and 2, we will have;

x < -3/2 and x>48/5

If x>48/5 then 48/5<x

Combining 48/5<x with x < -3/2  will give  48/5<x<-3/2

Other Questions