Answer:
The correct option is;
B. N'(1, 0), U'(3, 5), L'(5, 2), H'(3, -2)
Step-by-step explanation:
The coordinates of the pre-image are given as follows;
H(1, -5), N(-1, -3), U(1, 2), and L(3, -1)
The required transformation is T₍₂, ₃₎,which is a translation of (two) 2 units right and an additional translation of (three) 3 units up, which gives the coordinates of the image as follows;
N(-1, -3) transformed by N(-1 + 2, -3 + 3) [tex]\overset{T_{(2,\, 3)}}{\rightarrow}[/tex] N'(1, 0)
U(1, 2) transformed by U(1 + 2, 2 + 3) [tex]\overset{T_{(2,\, 3)}}{\rightarrow}[/tex] U'(3, 5)
L(3, -1) transformed by L(3 + 2, -1 + 3) [tex]\overset{T_{(2,\, 3)}}{\rightarrow}[/tex] L'(5, 2)
H(1, -5) transformed by H(1 + 2, -5 + 3) [tex]\overset{T_{(2,\, 3)}}{\rightarrow}[/tex] H'(3, -2)
The coordinates of the vertices of the given figure after the given transformation, T₍₂, ₃₎, are N'(1, 0), U'(3, 5), L'(5, 2), and H'(3, -2).
Therefore, the correct option is N'(1, 0), U'(3, 5), L'(5, 2), H'(3, -2).
