Answer :

FadedElla

[tex] \LARGE{ \boxed{ \red{ \rm{Answer}}}}[/tex]

☃️ Chemical formulae ➝ [tex]\sf{Al_2(CO_3)_3}[/tex]

How to find?

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

[tex] \boxed{ \sf{no. \: of \: moles = \frac{given \: weight}{molecular \: weight} }}[/tex]

Solution:

❍ Molecular weight of [tex]\sf{Al_2(CO_3)_3}[/tex]

= 2 × 27 + 3 × 12 + 9 × 16

= 54 + 36 + 144

= 234

❍ Given weight: 10 g

Then, no. of moles,

⇛ No. of moles = 10 / 234

⇛ No. of moles = 0.0427 moles

No. of moles of Aluminium carbonate in the given weight = 0.0427 moles.

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ok it’s gonna be the c= 12

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