Answer :
Answer:
The z-scores are [tex]Z_{\frac{\alpha }{2} } = 0643[/tex] and [tex]Z_{\frac{\alpha }{2} } = - 0643[/tex]
Step-by-step explanation:
From the question we are told that
The middle of the distribution area considered is 48%
Now the rest of the area under the standard normal distribution area is mathematically evaluated
[tex]\alpha = 100- 48[/tex]
[tex]\alpha = 52 \%[/tex]
[tex]\alpha = 0.52[/tex]
Now to obtain the area occupied by this proportion at the two tails we divide by 2 i.e
[tex]\frac{\alpha }{2} = \frac{0.52}{2} =0.26[/tex]
Now the z-score is obtained from the normal distribution table and the value is
[tex]Z_{\frac{\alpha }{2} } \pm 0.643[/tex]
The [tex]\pm[/tex] shows that we are considering the two-talil