Answer :
Answer:
7bright fringes
Explanation:
First we know that
Sinစ m,max= Mmax, x lambda/d
To find Mmax
Sin90° = Mmax x lambda/d = 1
So
Mmax= d/ lambda
= lambda= 500nm
d= 1/550mm
So
= 1.8 x10-6/500x 10^-9m
= 3.6
So m is approx 3
So 3 bright fringes above below and the central bright fringe itself making 7bright fringes