Answered

What is the maximum speed with which a 1200-kg car can round a turn of radius 90.0 m on a flat road if the coefficient of static friction between tires and road is 0.70?
2. Is this result independent of the mass of the car?

Answer :

Answer:

78.6m/s

Explanation:

We know that frictional force also contributes to the centripetal force that keeps the car in circular motion in the turn

And is given as

F= mv²/r

But the frictional force is

F= ugm

= = 0.7*1200*9.8= 8232N

To find maximum velocity v we say

V= √F x r/m

= √ 8232* 90 /1200

= 78.6m/s

2. Yes it is independent of mass of car

Answer:

The value is [tex]v = 24.85 \ m/s[/tex]

Yes

Explanation:

From the question we are told that

  The mass of the car is  [tex]m= 1200 \ kg[/tex]

    The  radius  is [tex]r = 90 \ m[/tex]

    The coefficient of static friction is  [tex]\mu_s = 0.70[/tex]

Generally at maximum speed the centripetal force acting on the car is equal to the friction force on the car

So

    [tex]F_c = F_f[/tex]

        [tex]\frac{m v^2}{r} = \mu_s * m * g[/tex]

=>   [tex]v = \sqrt{\mu_s * g * r }[/tex]

=>   [tex]v = \sqrt{ 0.70 * 9.8 * 90 }[/tex]

=>    [tex]v = 24.85 \ m/s[/tex]

Yes the value is independent of the mass because from the equation above we see that v is independent of mass

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