A line with a slope of -2/5 that passes through the point (-10,8)

Step-by-step explanation:
[tex]m = - \frac{2}{3} \\ ( - 10 ,\: 8) = (x_1,y_1)[/tex]
[tex]y-y_1=m(x-x_1)[/tex]
Plug in the values into the equation
[tex]y - 8 = - \frac{2}{3} (x - ( - 10)) \\ y - 8 = - \frac{2}{3}( x + 10) \\ [/tex]
[tex]y - 8 = - \frac{2}{3} x - \frac{20}{ 3 } \\ y = - \frac{2}{3} x - \frac{20}{3} + 8 \\ [/tex]
[tex]y = - \frac{2}{3} x + \frac{4}{3} [/tex]
To solve for x-intercept , Arrange the values in
[tex]ax + by + c = 0[/tex]
=
[tex] - \frac{2}{3} x - y + \frac{4}{3} = 0[/tex]
To find x-intercept .let y = 0 in the above equation
[tex] - \frac{2}{3} x - y + \frac{4}{3} = 0 \\ - \frac{2}{3} x - 0 + \frac{4}{3} = 0 \\ [/tex]
[tex] - \frac{2}{3} x + \frac{4}{3} = 0 \\ - \frac{2}{3} x = - \frac{4}{3} [/tex]
Solve for x ;
[tex]x = 2[/tex]
To find y intercept , let x = 0
and solve for y .
I hope it helps <3
y = mx + b
m = -²/₃ and line pases through (-10, 8) so:
8 = -²/₃(-10) + b
8 = ²⁰/₃ + b
b = 8 - ²⁰/₃
b = 8 - 6²/₃
b = 1¹/₃
b = ⁴/₃
Slope Intercept Form:
x-intercept:
-²/₃x + ⁴/₃ = 0
-²/₃x =- ⁴/₃
x = - ⁴/₃ ÷(-²/₃)
x = 2
y-intercept:
y = -²/₃•0+ ⁴/₃ = ⁴/₃