Answer :
Answer:
8.846 m/s²
Explanation:
From the question,
The magnitude of the average acceleration is given as,
a = (v-u)/t.................. Equation 1
Where a = acceleration of the jet, v = final velocity of the jet, u = initial velocity of the jet, t = time taken for the jet to come to rest.
Given: v = 115 m/s, u = 0 m/s( from rest), t = 13.0 s
Substitute these values into equation 1
a = (115-0)/13.0
a = 115/13
a = 8.846 m/s²
Hence the magnitude of the average acceleration of the jet is 8.846 m/s²
Answer:
The value is [tex]a = 8.85 \ m/s^2[/tex]
Explanation:
From the question we are told that
The speed is [tex]v = 115\ m/s[/tex]
The time taken is t = 13.0
The initial speed is [tex]u = 0 \ m/s[/tex]
Generally the magnitude of the average acceleration is mathematically represented as
[tex]a = \frac{v-u}{ t}[/tex]
=> [tex]a = \frac{ 115 -0}{ 13}[/tex]
=> [tex]a = 8.85 \ m/s^2[/tex]