Answer:
at ∠A sin Ф = 180 + (2 / [tex]\sqrt{22}[/tex] )
at ∠B cos Ф = 180 + (3[tex]\sqrt{2}[/tex] / [tex]\sqrt{22}[/tex] )
at ∠C tan Ф = 180 + (2 / 3[tex]\sqrt{2}[/tex] )
Step-by-step explanation:
let (a) = 3[tex]\sqrt{2}[/tex]
let (b) = 2
let (c) = r
to get the value of hypotenuse (r) use pythagorean theorem
a² + b² = c²
2² + (3[tex]\sqrt{2}[/tex] )² = c²
c = [tex]\sqrt{22}[/tex]
use the law of sines to get the value of angle A (point origin)
sin Ф = opp / hyp
cos Ф = adj / hyp
tan Ф = opp / adj
at ∠A
sin Ф = 180 + (2 / [tex]\sqrt{22}[/tex] )
at ∠B
cos Ф = 180 + (3[tex]\sqrt{2}[/tex] / [tex]\sqrt{22}[/tex] )
at ∠C
tan Ф = 180 + (2 / 3[tex]\sqrt{2}[/tex] )
