Answer:
73, 74, 75
Step-by-step explanation:
So the sum of three consecutive integers is 222.
Let's let the first integer be n.
Then the second integer must be (n+1).
And the third integer must be (n+2).
They total 222, thus:
[tex]n+(n+1)+(n+2)=222[/tex]
Combine like terms:
[tex]3n+3=222[/tex]
Subtract 3 from both sides:
[tex]3n=219[/tex]
Divide both sides by 3:
[tex]n=73[/tex]
So, the first integer is 73.
So our sequence is 73, 74, and 75.
And we're done!
