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A door with width 4.20m has an arc as shown in the diagram. Find: a) the radius of the arc, to the nearest cm. b) the length of the arc, to the nearest cm

A door with width 4.20m has an arc as shown in the diagram. Find: a) the radius of the arc, to the nearest cm. b) the length of the arc, to the nearest cm class=

Answer :

0Sad0Baby0Bunnies0

Hi there!

~

[tex]R = \frac{2.1}{sin 67.5}[/tex]

[tex]Arc = R[/tex] [tex]\frac{3\pi }{4}[/tex]

(A)

Hope this helped you!

${teks-lihat-gambar} 0Sad0Baby0Bunnies0
adwoaApp

Answer:

a. 2m

b. 5m

Step-by-step explanation:

a. from the triangle assuming ABC

half triangle ABC will be ABO and ACO

AO = OB = 4.20m ÷ 2

AO = OB = 2.1m

finding the angle between AB and AC

360 - 225 = 135°

the angle between AB and AO

135÷2= 67.5°

using sin to find the length of AB = radius

sin 67.5 = 2.1/r

r= 2.2730 ~2m

b. theta/360 ×2πr = length of the arc

L= 135/360×2×22/7 × 2.2730

Length of the arc = 5.3578m ~ 5m

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