Answer :
Given :
An equation , [tex]a=mg-\dfrac{kv^2}{m}[/tex] .
To Find :
The value of v in above equation if a = 2.8, m = 12, g = 9.8, k[tex]v=\sqrt{\dfrac{12(12\times 9.8-2.8)}{\dfrac{8}{3}}}\\\\v= \$22.73[/tex] = 8/3 .
Solution :
Simplifying the given statement in terms of v = ..... .
[tex]\dfrac{kv^2}{m}=mg-a\\\\v^2=\dfrac{m(mg-a)}{k}\\\\v=\sqrt{\dfrac{m(mg-a)}{k}}[/tex] ...... 1 )
Putting all given values in above equation , we get :
[tex]v=\sqrt{\dfrac{12(12\times 9.8-2.8)}{\dfrac{8}{3}}}\\\\v= 22.73[/tex]
Therefore , the value of v is 22.73 .
Hence , this is the required solution .