Answer :
Answer:
3.25 seconds
Explanation:
It is given that,
A person throws a baseball from height of 7 feet with an initial vertical velocity of 50 feet per second. The equation for his motion is as follows :
[tex]h=-16t^2+vt+s[/tex]
Where
s is the height in feet
For the given condition, the equation becomes:
[tex]h=-16t^2+50t+7[/tex]
When it hits the ground, h = 0
i.e.
[tex]-16t^2+50t+7=0[/tex]
It is a quadratic equation, we find the value of t,
t = 3.25 seconds and t = -0.134 s
Neglecting negative value
Hence, for 3.25 seconds the baseball is in the air before it hits the ground.