louaznaaya1
Answered

A car slows down from a velocity of 25 m/s to rest in 5.0 seconds. How far did the car travel during that time?

Answer :

Cathenna

Answer:

[tex] \boxed{\sf Distance \ travelled = 62.5 \ m} [/tex]

Given:

Initial velocity (u) = 25 m/s

Final velocity (v) = 0 m/s (Rest)

Time taken (t) = 5 seconds

To Find:

Distance travelled by car (s)

Explanation:

From equation of motion of object moving with uniform acceleration in straight line we have:

[tex] \boxed{ \bold{s = (\frac{v + u}{2} )t}}[/tex]

By substituting value of v, u & t in the equation we get:

[tex] \sf \implies s = ( \frac{0 + 25}{2} ) \times 5 \\ \\ \sf \implies s = \frac{25}{2} \times 5 \\ \\ \sf \implies s = 12.5 \times 5 \\ \\ \sf \implies s = 62.5 \: m[/tex]

[tex] \therefore[/tex]

Distance travelled by car (s) = 62.5 m