Answer:
[tex] EF = 5 [/tex]
[tex] GH = 5 [/tex]
Step-by-step explanation:
Length of EFis the distance between E(-4, -3) and F (-1, 1).
[tex] EF = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]
Let,
[tex] E(-4, -3) = (x_1, y_1) [/tex]
[tex] F(-1, 1) = (x_2, y_2) [/tex]
[tex] EF = \sqrt{(-1 -(-4))^2 + (1 -(-3))^2} [/tex]
[tex] EF = \sqrt{(3)^2 + (4)^2} [/tex]
[tex] EF = \sqrt{9 + 16} = \sqrt{25} [/tex]
[tex] EF = 5 [/tex]
Distance between G(-2, -3) and H(3, -3)
[tex] GH = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]
Let,
[tex] G(-2, -3) = (x_1, y_1) [/tex]
[tex] H(3, -3) = (x_2, y_2) [/tex]
[tex] GH = \sqrt{(3 -(-2))^2 + (-3 -(-3))^2} [/tex]
[tex] GH = \sqrt{(5)^2 + (0)^2} [/tex]
[tex] GH = \sqrt{25 + 0} = \sqrt{25} [/tex]
[tex] GH = 5 [/tex]
