Answer :

Stephen46

Answer:

The answer is option B

Step-by-step explanation:

The distance between two points can be found by using the formula

[tex]d = \sqrt{( {x1 - x2})^{2} + ({y1 - y2})^{2} } \\ [/tex]

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

( -2 , 1) and ( 4,3)

The distance is

[tex]d = \sqrt{( { - 2 - 4})^{2} + ({1 - 3})^{2} } \\ = \sqrt{ ({ - 6})^{2} + ({ - 2})^{2} } \\ = \sqrt{36 + 4} \\ = \sqrt{40} \\ = 2 \sqrt{10} \\ = \:6.324555[/tex]

We have the final answer as

6.3

Hope this helps you

Sueraiuka

Step-by-step explanation:

Hey there!!!

Given, the points are (4,3) and (-2,1).

Then,

x1=4 x2=-2

y1=3 y2=1

Now, Using distance formula,

[tex](distance ) = \sqrt{ {(x2 - x1)}^{2} + ( {y2 - y1)}^{2} } [/tex]

Put all values.

[tex](distance ) = \sqrt{ {( - 2 - 4)}^{2} + {(1 - 3)}^{2} } [/tex]

Simplify them.

[tex](distance ) = \sqrt{( { - 6)}^{2} + ( { - 2)}^{2} } [/tex]

[tex](distance ) = \sqrt{36 + 4} [/tex]

[tex](distance ) = \sqrt{40} [/tex]

(distance )= 6.3245 units.

Therefore, the distance between the points(4,3) and (-2,1) is 6.32units.

So, your answer is option B.

Hope it helps....

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