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Find four consecutive even integers such that the sum of twice the last integer and the second integer is 212.

Answer :

CSMedrano

Answer:

it's not possible

Step-by-step explanation:

let's say that we have

[tex]x,x+1,x+2,x+3[/tex]

so twice the last integer is

[tex]2(x)\\\\=2x[/tex]

and the second integer is

[tex]x+1[/tex]

so the sum of both is 212

[tex]2x+x+1=212\\\\3x+1=212\\\\3x+1-1=212-1\\\\3x=211\\\\x=70.3333...[/tex]

so as we can see there aren't those integers

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