Answer :
Answer:
d = -11.025 m
Explanation:
Given that,
An egg is dropped from a treehouse and takes 1.5 seconds to reach the ground. We need to find the egg's displacement. It can be calculated using second equation of motion as follows :
[tex]s=ut+\dfrac{1}{2}at^2[/tex]
u is initial speed, the initial speed of egg is 0 as it was at rest initially.
a = -g (as the stone is coming downward direction)
t is time.
si is egg's displacement
[tex]s=0-\dfrac{1}{2}gt^2\\\\s=\dfrac{1}{2}\times 9.8\times 1.5^2\\\\d=-11.025[/tex]
-ve sign shows the displacement of the egg in opposite direction of its motion and its magnitude is 11.025 meters.