What is the solution set of this inequality?
[tex]8(x - 5) - 3x \geqslant - 20[/tex]




A.
[tex]x \geqslant 4[/tex]
B.
[tex]x \geqslant - 3[/tex]
C.
[tex]x \leqslant - 12[/tex]
D.
[tex]x \leqslant 12[/tex]


Answer :

Answer:

A.

[tex]x\ge \:4[/tex]

Step-by-step explanation:

[tex]8(x-5) -3x\geq -20\\\\\mathrm{Expand\:}8\left(x-5\right)-3x:\quad 5x-40\\\\5x-40\ge \:-20\\\\\mathrm{Add\:}40\mathrm{\:to\:both\:sides}\\\\5x-40+40\ge \:-20+40\\\\Simplify\\\\5x\ge \:20\\\\\mathrm{Divide\:both\:sides\:by\:}5\\\\\frac{5x}{5}\ge \frac{20}{5}\\\\Simplify\\\\x\ge \:4[/tex]

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