(1 point) In a random sample of 1,000 people, it is found that 6.3% have a liver ailment. Of those who have a liver ailment, 7% are heavy drinkers, 55% are moderate drinkers, and 38% are nondrinkers. Of those who do not have a liver ailment, 14% are heavy drinkers, 44% are moderate drinkers, and 42% are nondrinkers. If a person is chosen at random, and he or she is a heavy drinker, what is the empirical probability of that person having a liver ailment? 0.00854217

Answer :

Answer:

P(liver ailment | heavy drinker) = 0.087*0.08 = 0.00696

Ans: # = 0.00696*1000 = 6.96 or approximately 7

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