Answer:
B. 26.0 μL.
Explanation:
Hello,
In this case, taking into account that given the mass and density, the volume is computed to be:
[tex]V=\frac{m}{\rho} =\frac{25.000mg}{0.788g/mL}*\frac{1g}{1000mg}*\frac{1000\mu L}{1mL} \\ \\V=26.0\mu L[/tex]
Thus, answer is B. 26.0 μL.
Best regards.
