Answer :

CSMedrano

Answer:

No

Step-by-step explanation:

for a n-agon the formula is

[tex]\frac{n(n-3)}{2}[/tex]

so in our case n=10

[tex]\frac{(10)(10-3)}{2} \\\\=\frac{10*7}{2} \\\\=5*7\\\\=35[/tex]

so no, a 10 side polygon has exactly 35 diagonals

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