Need Helpp!!!!

A pitcher throws a ball to a batter, who hits the ball to the shortstop. If the ball travels in a straight line between each,
•What is the total distance traveled by the ball ? Round your answer to the nearest tenth of a foot.

Need Helpp!!!! A pitcher throws a ball to a batter, who hits the ball to the shortstop. If the ball travels in a straight line between each, •What is the total class=

Answer :

Answer:

Distance traveled by the ball will be 87.1 feet.

Step-by-step explanation:

Length of a segment between extreme ends [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by,

d = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Coordinates of batter and shortstop are (9, 9) and (45, 90) (in feet) respectively.

Batter hits the ball and the ball moves in a straight line.

Therefore, distance between batter and the shortstop will be,

d = [tex]\sqrt{(9-45)^2+(9-90)^2}[/tex]

  = [tex]\sqrt{(-36)^2+(-81)^2}[/tex]

  = [tex]\sqrt{1296+6561}[/tex]

  = [tex]\sqrt{7587}[/tex]

  = 87.10

  ≈ 87.1 feet

Therefore, distance traveled by the ball will be 87.1 feet.

abidemiokin

The total distance traveled by the ball to the nearest tenth is 86.5 feet

If the ball travels in a straight line between each point, the total distance traveled by the ball will be gotten using the distance formula expressed as:

[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Using the coordinate of the pitcher and the batter and shortstop (9, 9) and (45, 90) respectively.

Substitute into the formula to have:

[tex]D=\sqrt{(90-9)^2+(45-9)^2}\\D=\sqrt{(81)^2+36^2}\\D = \sqrt{6561+1296} \\D=\sqrt{7857}\\D= 86.64feet[/tex]

Hence the total distance traveled by the ball to the nearest tenth is 86.5 feet

Learn more here: https://brainly.com/question/22624745

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