Answered

What is wrong with the equation? 2 x−3 dx = x−2 −2 2 −3 = − 5 72 −3 f(x) = x−3 is continuous on the interval [−3, 2] so FTC2 cannot be applied. f(x) = x−3 is not continuous at x = −3, so FTC2 cannot be applied. f(x) = x−3 is not continuous on the interval [−3, 2] so FTC2 cannot be applied. There is nothing wrong with the equation. The lower limit is less than 0, so FTC2 cannot be applied.

Answer :

batolisis

Answer:

Hello your question is incomplete below  is the complete question

What is wrong with the equation? integral^2 _3 x^-3 dx = x^-2/-2]^2 _3 = -5/72 f(x) = x^-3 is continuous on the interval [-3, 2] so FTC2 cannot be applied. f(x) = x^-3 is not continuous on the interval [-3, 2] so FTC2 cannot be applied. f(x) = x^-3 is not continuous at x = -3, so FTC2 cannot be applied The lower limit is less than 0, so FTC2 cannot be applied. There is nothing wrong with the equation. If f(2) = 14, f' is continuous, and f'(x) dx = 15, what is the value of f(7)? F(7) =

answer : The value of f(7) = 29

Step-by-step explanation:

Attached below is the detailed solution

Hence : F(7) - 14 = 15

F(7) = 15 + 14 = 29

${teks-lihat-gambar} batolisis

Other Questions