Answer :
Answer:
[tex] \huge{ \boxed{ \tt{75.9}\sf \: {m}^{2} }}[/tex]
Step-by-step explanation:
[tex] \underline{ \sf{Given}} : [/tex]
[tex] \star{ \sf{ \: Height \: of \: a \: parallelogram \: (h) \: = 11m}}[/tex]
[tex] \star{ \sf{ \: Base \: of \: a \: parallelogram \: (b) \: = 6.9m}}[/tex]
[tex] \underline{ \sf{Finding \: the \: area \: of \: the \: parallelogram \: having \: height \: of \: 11m \: and \: base \: of \: 6.9m}} : [/tex]
[tex] \boxed{ \sf{Area \: of \: parallelogram = base \: ∗ \: height}}[/tex]
[tex] \mapsto{ \sf{Area \: of \: parallelogram = 6.9m \: ∗ \: 11m}}[/tex]
[tex] \mapsto{ \sf{Area \: of \: a \: parallelogram = 75.9 \: {m}^{2} }}[/tex]
Hope I helped!
Best regards! :D
~[tex] \sf{TheAnimeGirl}[/tex]
[tex] \huge\sf {\dag Question} [/tex]
If the height of a parallelogram is 11m and the base is 6.9m, what is the area of the parallelogram?
[tex] \huge\sf {\dag Solution } [/tex]
[tex] {\underline {\underline {\rm { Given:}}}} [/tex]
- h ( height of the parallelogram ) = 11m
- b ( base of the parallelogram ) = 6.9m
[tex] {\underline {\underline {\rm { To \: find :}}}} [/tex]
- Area of the parallelogram
[tex] {\underline {\underline {\rm { Calculation :}}}} [/tex]
We know that,
[tex] {\underline {\underline {\rm {\red { Ar. \: of \: parallelogram = h \times b}}}}} [/tex]
Substituting values-
[tex] \sf {\implies Ar. \: of \: parallelogram = 11 \times 6.9}[/tex]
[tex] \sf {\implies Ar\: of \: parallelogram = 75.9{m}^{2}}[/tex]