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A rectangular garden has a perimeter of 172 feet. The length of the garden is 24 feet more than the width. What are the dimensions of the garden? (Recall the formula P = 2L + 2W.)

Answer :

Let the width be x, then length = 24 +x
Perimeter = 2(length + width)
2(x + 24 + x) = 172
2(2x + 24) = 172
4x - 48 = 172
4x = 172 + 48 = 220
x = 220/4 = 55

Therefore, width is 55 and length is 55 + 24 = 79

Answer:

Perimeter of a rectangle is given by:

[tex]P= 2(L+W)[/tex]        .....[1]

where

P is the perimeter of a rectangle

L is the length of the rectangle

W is the width of the rectangle.

As per the statement:

A rectangular garden has a perimeter of 172 feet.

⇒P = 172 feet

It is also given that:

The length of the garden is 24 feet more than the width.

⇒[tex]L= 24+W[/tex]

Substitute the given values in [1] we have;

[tex]172=2(24+W+W)[/tex]

Combine like terms;

[tex]172=2(24+2W)[/tex]

Divide both sides by 2 we have;

[tex]86=24+2W[/tex]

Subtract 24 from both sides we have;

[tex]62=2W[/tex]

Divide both sides by 2 we get;

31 feet = W

Then;

[tex]L= 24+31 = 55[/tex] feet.

therefore, the dimension of the garden are:

[tex]L= 55[/tex] feet and W = 31 feet

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